Factoring
Factor quadratics.
Try ToolStep-by-step solutions by different methods
Learn how to solve quadratic equations using factoring, completing the square, and the quadratic formula.
Step 1: Recognize \(x^2 - 3^2\)
Step 2: Factor: \((x - 3)(x + 3) = 0\)
Answer: \(x = 3\) or \(x = -3\)
Step 1: Find factors of 6 that sum to 5: 2 and 3
Step 2: Factor: \((x + 2)(x + 3) = 0\)
Answer: \(x = -2\) or \(x = -3\)
Step 1: \(a \times c = 2 \times (-3) = -6\)
Step 2: Factors of -6 that sum to -5: -6 and 1
Step 3: Factor: \((2x + 1)(x - 3) = 0\)
Answer: \(x = -\frac{1}{2}\) or \(x = 3\)
a=1, b=-4, c=2
\(x = \frac{4 \pm \sqrt{16-8}}{2} = \frac{4 \pm \sqrt{8}}{2}\)
Answer: \(x = 2 \pm \sqrt{2}\)
a=3, b=2, c=-1
\(x = \frac{-2 \pm \sqrt{4+12}}{6} = \frac{-2 \pm 4}{6}\)
Answer: \(x = \frac{1}{3}\) or \(x = -1\)
Discriminant: \(1 - 4 = -3\)
\(x = \frac{-1 \pm i\sqrt{3}}{2}\)
Answer: Complex roots
Step 1: \(x^2 + 6x = -5\)
Step 2: Add 9: \(x^2 + 6x + 9 = 4\)
Step 3: \((x+3)^2 = 4\)
Answer: \(x = -1\) or \(x = -5\)
Step 1: Divide by 2: \(x^2 - 4x = 5\)
Step 2: Add 4: \((x-2)^2 = 9\)
Answer: \(x = 5\) or \(x = -1\)
| Equation | Discriminant | Roots | Type |
|---|---|---|---|
| \(x^2 - 5x + 6 = 0\) | 1 | 2, 3 | Two Real |
| \(x^2 - 4x + 4 = 0\) | 0 | 2 | Double |
| \(x^2 + 1 = 0\) | -4 | ±i | Complex |